Cudamemcpy to symbol example. To figure out what is copy unit of cudaMemcpy() and transport unit of cudaMalloc(), I wrote the below code, which adds two vectors,vector1 and vector2, and stores resul How will the cudaMemcpy function work in this case? I have declared a matrix like this float imagen[par->N][par->M]; and I want to copy it to the cuda device so I did this float *imagen_c Sep 4, 2025 · CUDA Runtime API (PDF) - v13. Sep 15, 2016 · To access from host, you need cudaMemcpyToSymbol. 000. An example: This entry was posted in cuda, programming. Nov 26, 2011 · It seems common to use cudaMemcpyToSymbol and cudaMemcpyFromSymbol to link global device variables to a device memory block. Calling cudaMemcpy () with dst and src pointers that do not match the direction of the copy results in an Dec 14, 2008 · Hi, This is probably a stupid question, but I don’t know how to use the cudaMemCpyToSymbol correctly. kind can be either cudaMemcpyDeviceToHost or . Consider a constant memory array: To copy values to this array using cudaMemcpyToSymbol, just do. Now, I would like to avoid to use functions like copyBary since it “contains” the bary variable; i would like to pass the destination symbol as an argument. Copies count bytes from the memory area pointed to by offset bytes from the start of symbol symbol to the memory area pointed to by dst. It is useful to copy some dimension parameters to constant memory (64K for Fermi and up). The memory areas may not overlap. Bookmark the permalink. To make my questions clear, a little program is given below. However, I never saw any clear description about these functions. So let’s say I have the following simplified example… Jan 7, 2022 · I'learning CUDA programming. 0. ) Results: 0x500500500: float[320]= 1. *a=3; int *da; cudaMalloc(&da,1*sizeof(int)); cudaMemcpyToSymbol(a,&da,sizeof(int*)); Copies count bytes from the memory area pointed to by src to the memory area pointed to by offset bytes from the start of symbol symbol. 8 and I activated the switch -rdc=true Copies count bytes from the memory area pointed to by src to the memory area pointed to by dst, where kind is one of cudaMemcpyHostToHost, cudaMemcpyHostToDevice, cudaMemcpyDeviceToHost, or cudaMemcpyDeviceToDevice, and specifies the direction of the copy. I’m trying to copy local host memory to constant device memory. (But cudaMemcpy does. (If I remove the second copy, the first copy works fine. Apr 4, 2023 · If I use one of the other two methods, the kernel finds the constant memory filled by zeros. Mar 13, 2013 · I'm trying to figure out why cudaMemcpyToSymbol is not working for me. 0 (older) - Last updated August 1, 2025 - Send Feedback Copies count bytes from the memory area pointed to by offset bytes from the start of symbol symbol to the memory area pointed to by dst. To do the same with cudaMemcpy requires this: cudaGetSymbolAddress((void **)&dcoeffs, coeffs); Copies count bytes from the memory area pointed to by src to the memory area pointed to by offset bytes from the start of symbol symbol. Apr 13, 2013 · In short, because cudaMemcpy can't do the same thing as cudaMemcpyToSymbol without an additional API call. ) The second copy is trashing the contents of the first copy (flt), and the second copy does not happen. symbol can either be a variable that resides in global or constant memory space, or it can be a character string, naming a variable that resides in global or constant memory space. How can I do? NOTE ADDED: I’m using cuda 11. 866. 0x500500504: float[321]= 0. klcbx zvsqq tbkkw ybgawx mmoo rgfljs fejwp vdamunfu mgf rhfko